Question

What is the domain of the function
f(x)= square root of (1/3)x+2?

Answer 1

The domain of f(x) = √[(1/3)x +2] is [-6, ∞).

Explanation:

GIven f(x) = √[(1/3)x +2], you have to find the values for which the the expression inseide the square will be possitive (for negative values the function is not defined for Reals.

(1/3)x + 2 = 0 ⇒ (1/3)x = -2 ⇒ x = -2/(1/3) ⇒ x = -6

Finally the domain of f(x) is (-6, ∞).

Answer 2

✔️ X
`\geq` -6