Answer:
The area of circle 1 is 9 times greater than area of circle 2.
Explanation:
Given that:
Radius of circle 1 = 12
Area of circle 1 = πr²
Area of circle 1 =
![3.14*(12)^2 = 3.14*144](https://img.qammunity.org/2022/formulas/mathematics/high-school/g9ritt0xvqj3epg2ia0bvp41jg0yhvpu9c.png)
Area of circle 1 = 452.16
Radius of circle 2 = 4
Area of circle 2 =
![3.14*(4)^2 = 3.14*16](https://img.qammunity.org/2022/formulas/mathematics/high-school/zsg6bkdsuvj3krw3eyg80h8jiblgne65hr.png)
Area of circle 2 = 50.24
Let,
x be the number of times circle 1 is bigger than circle 2.
Area circle 1 = x * Area circle 2
![(452.16)/(50.24)=(50.24x)/(50.24)\\\\x=9](https://img.qammunity.org/2022/formulas/mathematics/high-school/m9z0dih5a95qg0qu396hco258mxqli77js.png)
Hence,
The area of circle 1 is 9 times greater than area of circle 2.