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Find the perimeter of a rectangle of which length is 5 more than the width

User Squeegy
by
6.0k points

2 Answers

2 votes

Answer:

P = 4W + 10

Explanation:

Perimeter is 2 × (length + width)

let length be L and width be W

if length is 5 more than width

L = W + 5

P = 2(L + W)

P = 2(W + 5 + W)

P = 2(2W + 5)

P = 4W + 10

User MaBbKhawaja
by
6.1k points
4 votes

Answer:

the perimeter= 10+4W.

where W= the width.

Explanation:

mathematically, perimeter (p)= 2L +2W

where L= length.and W=width

from the expression ;length is 5 more than the width

it is written as L = 5+W

substitute in the formula

P= 2(5+W)+2W

P=10+2W+2W

P=10+4W as the perimeter of the rectangle.

User Edwardo
by
5.3k points