Question

X^3-64 in factored form​

Answer 1

`[{x}^(2) + 4x + 16][x - 4]`

Step-by-step explanation:

Take the cube root of this expression using the Difference of Cubes [(a + b)(a² - 2ab + b²)]:

`x - 4 = \sqrt[3]{{x}^(3) - 64}`

Now, since the divisor\factor is in the form of
`x - c`, use what is called Synthetic Division. Remember, in this formula, −c gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:

4| 1 0 0 −64

↓ 4 16 64

__________

1 4 16 0 →
`{x}^(2) + 4x + 16`

You start by placing the c in the top left corner, then list all the coefficients of your dividend [x³ - 64]. You bring down the original term closest to c then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an x², the 4x follows right behind it, and bringing up the rear, 16, giving you the other factor of
`{x}^(2) + 4x + 16`. Attach this to the first factor you started out your work on:

`[x - 4][{x}^(2) + 4x + 16]`

I am joyous to assist you anytime.

Answer 2

Answer: (x−4)(x2+4x+16)

Explanation:

x^3 − 64 ←is a difference of cubes

. xa^3 −b^3 = ( a − b ) (a^2 + ab + b^2)

here a = x and b =4 → (4)^3 = 64

⇒ x^3 − 64 = (x − 4) (x^2 + 4x + 16 )