Question

A bullet is fired straight up from a gun with a muzzle velocity of 136 m/s. Neglecting air resistance, what will be its displacement after 1.3 s? The acceleration of gravity is 9.8 m/s 2 . Answer in units of m.

Answer 1

Step-by-step explanation:

Given that,

Speed with which the bullet is fired, u = 136 m/s

Time, t = 1.3 s

We need to find the displacement of the bullet after 1.3 seconds. It can be calculated using second equation of motion as :

`s=ut+(1)/(2)at^2`

Here, a = -g

`s=ut-(1)/(2)gt^2`

`s=136* 1.3-(1)/(2)* 9.8* (1.3)^2`

s = 168.51 meters

So, the displacement of the bullet after 1.3 seconds is 168.51 meters. Hence, this is the required solution.