Answer:

is the equation describing minimum and maximum acceptable temperatures.
The minimum temperature could be

and the maximum temperature could be

Explanation:
The owner of a butcher shop keeps the shop's freezer at -5°C. It is acceptable for the temperature to differ from this value by 1.5°. So, the minimum temperature could be

and the maximum temperature could be

Let
be acceptable temperature of freezer. The difference between the acceptable temperature and given temperature
cannot be more than 1.5° and less than 1.5°, so

Then

is the equation describing minimum and maximum acceptable temperatures.
Solve it:
