Question

Gold is a very soft metal that can be hammered into extremely thin sheets known as gold leaf. If a 1.78 g piece of gold is hammered into a sheet whose area is 48.4 ft2, what is the average thickness of the sheet? (The density of gold is 19.32 g cm-3.) 9.917*10^-5 cm

Answer 1

`2.0489* 10^(-6) cm` is the average thickness of the sheet.

Step-by-step explanation:

Mass of gold ,m= 1.78 g

Volume of the gold = V

Density of the gold = D =
`19.32g/cm^3`

`D=(m)/(V)=19.32g/cm^3=(1.78 g)/(V)`

`V = 0.09213 cm^3`

Area of the hammered gold sheet,A =
`48.4 ft^2=44,965.052 cm^2`

Thickness of the hammered gold = h

(
`1 ft^2=929.03 cm^2`)

Volume = Area × thickness

`V= A* h`

`0.09213 cm^3=44,965.052 cm^2* h`

`h=2.0489* 10^(-6) cm`

`2.0489* 10^(-6) cm` is the average thickness of the sheet.