Question

3. If a car accelerates from rest at a constant 5.5 m/s, how long will it take for the car to reach a

velocity of 28 m/s?​

Answer 1

Answer: 2.54 s

Step-by-step explanation:

If we are talking about a constant acceleration, we can use the following equation:

`V_(f)=V_(o)+2at`

Where:

`V_(f)=28 m/s` is the final velocity of the car

`V_(o)=0t` is the finitial velocity of the car (it started from rest)

`a=5.5 m/s^(2)` is the constant acceleration of the car

`t` is the time it takes to reach
`V_(f)` with the given constant velocity

Hence:

`V_(f)=2at`

Clearing
`t`:

`t=(V_(f))/(2a)`

`t=(28 m/s)/(2a(5.5 m/s^(2)))`

Finally:

`t=2.54 s`