Question

The magnitude of the electrostatic force between two identical ions that are separated by a distance of 5.0A is 3.7×10^-9N.a) what is the charge of each ion?b) how many electrons are missing from each ion( thus giving the ion its charge imbalance)?

Answer 1

Step-by-step explanation:

Given that,

Electrostatic force,
`F=3.7* 10^(-9)\ N`

Distance,
`r=5\ A=5* 10^(-10)\ m`

(a)
`F=(kq^2)/(r^2)`, q is the charge on the ion

`q=\sqrt{(Fr^2)/(k)}`

`q=\sqrt{(3.7* 10^(-9)* (5* 10^(-10))^2)/(9* 10^9)}`

`q=3.2* 10^(-19)\ C`

(b) Let n is the number of electrons are missing from each ion. It can be calculated as :

`n=(q)/(e)`

`n=(3.2* 10^(-19))/(1.6* 10^(-19))`

n = 2

Hence, this is the required solution.