Answer:Average speed is greater than average velocity.
Explanation :
Given
student walks slowly along a straight line for a while ,then stops to rest a while, and finally runs quickly back to her initial position
Let x be the length of track and the whole process takes t time
For average speed
![=(distance\ traveled)/(time\ taken)](https://img.qammunity.org/2020/formulas/physics/college/adihim8d3mv4hxwlum56xa4cb59w8y3267.png)
Average speed
![=(2x)/(t)](https://img.qammunity.org/2020/formulas/physics/college/28e9gah41du5uy5smt99zi67fnd3lo7gmu.png)
For average velocity
![=(Displacement)/(time\ taken)](https://img.qammunity.org/2020/formulas/physics/college/djqd5w6hmyk1ksdkz441rwcvusvsyzmdpn.png)
Since displacement is zero as she returns to its initial position.
Average velocity=0
Therefore Average speed is greater than average velocity.