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A student stays at her initial position for a bit of time, then walks slowly in a straight line for a while, then stops to rest a while, and finally runs quickly back to her initial position along a straight line. Which of the following statements is true about the average speed and the magnitude of the average velocity of the student during her trip? Her average speed is greater than the magnitude of her average velocity. Her average speed is the same as the magnitude of her average velocity. Her average speed is less than the magnitude of her average velocity. The student's average speed and velocity cannot be compared without knowing the farthest point she reached.

User Laishiekai
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Answer:Average speed is greater than average velocity.

Explanation :

Given

student walks slowly along a straight line for a while ,then stops to rest a while, and finally runs quickly back to her initial position

Let x be the length of track and the whole process takes t time

For average speed
=(distance\ traveled)/(time\ taken)

Average speed
=(2x)/(t)

For average velocity
=(Displacement)/(time\ taken)

Since displacement is zero as she returns to its initial position.

Average velocity=0

Therefore Average speed is greater than average velocity.

User Sagrario
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