Question

What is the molality of 10 kilograms of water containing 5.0 moles of sodium chloride?

Answer 1

molality ( m ) = 0.5 mol/Kg

Step-by-step explanation:

• molality ( m ) = mol solute / Kg solvent

∴ solute: NaCl

∴ solvent: H2O

⇒ m = 5.0 mol / 10 Kg

⇒ m = 0.5 mol NaCl / Kg H2O