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Solve the right triangle. Round lengths to the nearest tenth and angles to the nearest degree

Solve the right triangle. Round lengths to the nearest tenth and angles to the nearest-example-1

2 Answers

6 votes

Answer:

The answer to your question is:

AC length = 1.7 cm

∠A = 30.7°

∠ B = 59.3 °

Explanation:

To find the length of AC, we use the pythagorean theorem:

c² = a² + b² but we need to find a Ac which is a leg so we clear a from the equation

a² = c² - b²

a² = 3.28² - 2.8²

a² = 10.8 - 7.8

a² = 3

a = 1.7 cm

To find ∠A we use the sine function

sine Ф = AC / AB = 1.7/3.28 = 0.51

Then ∠A = sine-1 = 30.7°

To find ∠B = 180 - 90- 30.7 = 59.3°

User OzB
by
5.0k points
5 votes

Answer:

The answer to your question is:

AC length = 1.7 cm

∠A = 30.7°

∠ B = 59.3 °

Explanation:

To find the length of AC, we use the pythagorean theorem:

c² = a² + b² but we need to find a Ac which is a leg so we clear a from the equation

a² = c² - b²

a² = 3.28² - 2.8²

a² = 10.8 - 7.8

a² = 3

a = 1.7 cm

To find ∠A we use the sine function

sine Ф = AC / AB = 1.7/3.28 = 0.51

Then ∠A = sine-1 = 30.7°

To find ∠B = 180 - 90- 30.7 = 59.3°

User Ncuillery
by
5.2k points