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What Is the equation of the graph?

y=7/4x-5/2
y=3/2x-5/2
y=5/2x+3/2
y=-5/2x+3/2​

What Is the equation of the graph? y=7/4x-5/2 y=3/2x-5/2 y=5/2x+3/2 y=-5/2x+3/2​-example-1
User Haoyu Chen
by
8.1k points

2 Answers

4 votes

Answer:

A

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, - 2.5) and (x₂, y₂ ) = (2, 1) ← 2 points on the line

m =
(1+2.5)/(2-0) =
(3.5)/(2) =
(7)/(4)

Note the line crosses the y- axis at (0, - 2.5) ⇒ c = - 2.5 = -
(5)/(2)

y =
(7)/(4) x -
(5)/(2) → A

User Gnowoel
by
8.1k points
3 votes

Answer:
y=(7)/(4)x-(5)/(2)

Explanation:

The equation of a line passing through points (a,b) and (c,d) is given by :-


(y-b)=(d-b)/(c-a)(x-a)

From the given graph , it can be seen that the line is passing through (0,-2.5) and (2,1).

Then, the equation of line passing through (0,-2.5) and (2,1) will be:-


(y-1)=(1-(-2.5))/(2-0)(x-2)\\\\\Rightarrow\ (y-1)=(1+2.5)/(2)(x-2)\\\\\Rightarrow\ y-1=(3.5)/(2)(x-2)\\\\\Rightarrow\ y-1=(7)/(4)(x-2) \ \ [\because 3.5=(7)/(2)]\\\\\Rightarrow\ y-1=(7)/(4)x-(7)/(4)*2\\\\\Rightarrow\ y=(7)/(4)x-(7)/(2)+1\\\\\Rightarrow\ y=(7)/(4)x+(-7+2)/(2)\\\\\Rightarrow\ y=(7)/(4)x-(5)/(2)

Hence, the equation of the graph is
y=(7)/(4)x-(5)/(2)

User Drexsien
by
8.0k points

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