Question

The amplitude of the electric field of an electromagnetic wave traveling in a vacuum is measured to be 3.5 x 10^2 v/m. What is the amplitude of the magnetic field in this wave?

Answer 1

Answer:
`B=1.166 * 10^(-6) T`

Step-by-step explanation:

Given

Amplitude of Electric field is
`3.5* 10^2`

We know the relation between Electric field and Magnetic field is

E=cB

Where

E=Electric Field

c=speed of light

B=Magnetic field

`B=(E)/(c)`

`B=(3.5* 10^2)/(3* 10^8)`

`B=1.166 * 10^(-6) T`