Question

(x-6)² + (x + 5)² = 16

In the xy-plane, the graph of the equation above is a
circle. Point P is on the circle and has coordinates
(10,--5). If PQ is a diameter of the circle, what are
the coordinates of point Q?
A) (2, 5)
B) (6,-1)
C) (6,-5)
D) (6,-9)​

Answer 1

it (2,-5)

Explanation:

just did it

Answer 2

answer A : (2 -5)

Explanation:

the midipoint P,Q is the center A of this circle (because PQ is a diameter)

use : (x-6)²+(x+5)² = 16 you have : A(6 , -5) now let Q(x,y) :

(x+10)/2 = 6

(y-5)/2 = - 5

x+10 = 12

y-5 = -10

so : x = 2 and y = - 5....answer A : (2 -5)