Question

The Hall effect can be used to calculate the charge-carrier number density in a conductor. A conductor carrying current of 2.0 A is 0.50 mm thick, and the Hall voltage is 4.5 x 10-6 V when it is in a uniform magnetic field of 1.2 T. What is the density of charge carriers in the conductor? a) n = 4.6 x 1027 charges/m b) n = 1.7 x 1027 charges/m c) n = 1.0 x 1028 charges/m d) n = 6.7 x 1027 charges/m²

Answer 1

option D

Step-by-step explanation:

given,

A conductor is carrying current = 2.0 A is 0.5 mm thick

Hall voltage = 4.5 x 10-6 V

uniform magnetic field = 1.2 T

density of the charge = n =?

hall voltage =
`V_h =(i\ B)/(n\ e\ L)`

`n = (i\ B)/(V\ e\ L)`

`n = (2 * 1.2 )/(4.5 * 10^(-6)* 1.6 * 10^(-19) * 0.5 * 10^(-3))`

n = 6.67 × 10²⁷ charges/m

hence the correct answer is option D