Answer:
![A=\left[\begin{array}{ccc}3&0&0\\0&3&0\\0&0&3\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/college/d4joq7deygofizzdlw3237nl10joa28m09.png)
Explanation:
Our dimension vector is:
![v=\left[\begin{array}{c}x\\y\\z\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/college/gck1rrb7kudh9vp5poiqcz6aurmajgdvuw.png)
We need a matrix that returns another 3x1 vector, where only each component is 3 times the original value.
Let's see for x:
![X=A*\left[\begin{array}{c}x\\y\\z\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/college/okz0txo7oufzoyaz7lljmcy24v6s1la6gi.png)
if
![A=\left[\begin{array}{ccc}a&b&c\\d&e&f\\g&h&i\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/college/1yteoo8znvpgf379c1f0cx2br0ve130ncr.png)
then:
a*x+b*y+c*z=3*x then, b=c=0 and a=3
d*x+e*y+f*z=3*y then, d,f=0 and e=3
g*x+h*y+i*z=3*z then g,h=0 and i=3