Answer:
Yes. r>1
Explanation:
First we write the information we have.
2<m<p and m and p are integers
(1) The greatest common factor is 2. So we can say
2 is a factor of m and p.
(3) The minimum common multiple of m and p is 30.
So we can say that 30 can be divided by m and also by p.
So we will write all the dividers of 30.
1 ; 2 ; 3 ; 5; 6; 10; 15; 30
Of all this integers, the only ones that can be divided by 2 are:
2. 6 and 10.
Also, we know that m is not a factor of p. So we know that it cant be 2. because both 6 and 10 can be divided by 2.
That means m = 6 and p = 10.
So if r is the remainder of p divided by m. When we divided 10 by 6, we have a remainder of 4. r=4. Then r>1.