Answer:
football player decceleration is 70.01 m/s^2
Step-by-step explanation:
given data:
x = 0.360
initial velocity vi = 7.10m/s
final velocity vf = 0 m/s
we know that acceleration is given as a
![a =( vf^2 -vi^2)/(2x)](https://img.qammunity.org/2020/formulas/physics/high-school/hu22kasfgykbfz2mwlud5dj8w0asvdsu8h.png)
putting all value to get the desired value of acceleration:
![a = ( -(7.10)^2)/(2*.360)](https://img.qammunity.org/2020/formulas/physics/high-school/2ib9r4z5lukw4zq508ioamnvb6mupx27ja.png)
a = - 70.01 m/s^2
negative sign indicate deceleration
football player decceleration is 70.01 m/s^2