Question

For the reaction C6H6 + ? O2 → ? CO2+? H2O , what is the maximum amount of CO2 which could be formed from 6.59 g of C6H6 and 6.62 mol of O2? Answer in units of g.

Answer 1

Answer: 3.52 grams

Step-by-step explanation:

`2C_6H_6+15O_2\rightarrow 12CO_2+6H_2O`

Given moles:

moles of oxygen = 6.62

moles of
`C_6H_6=\frac{\text {given mass}}{\text {molar mas}}=(6.59g)/(78g/mol)=0.08moles`

According to stoichiometry:

2 moles of benzene reacts with = 15 moles of oxygen

Thus 0.08 moles of benzene will react with =
`(15)/(2)* 0.08=0.6` moles of oxygen

Thus benzene is the limiting reagent as it limits the formation of products and oxygen is the excess reagent.

As 2 moles of benzene produce = 12 moles of carbon dioxide

0.08 mole of benzene will produce =
`(12)/(2)* 0.08=0.48moles` of carbon dioxide

Mass of carbon dioxide=
`moles* {\text {Molar mass}}=0.48* 44=3.52g`

Thus 3.52 g of carbon dioxide are produced.