Answer:
Vout=6.83 v
Step-by-step explanation:
The resolution steps are going to be from 0.00366 V from the DAC and from the ADC, with 12 bits resolution and VFS =15v
Because, 12 bits resolution means
binary numbers, or 4096 positions. So to obtain the resolution in volts, is neccesary to divide the max input voltage in 4096.

Then Vin=6.83, so the output from the ADC is Vin/Voltage_step

in base 2: ADC out= 011101001010
Now, this is the same DAC input= 011101001010
And to calculate the output we multiply by the same resolution step
