Answer:
0.122 m/s
Step-by-step explanation:
mass of first train, m1 = 150,000 kg
initial velocity of first train, u1 = 0.3 m/s
mass of second train, m2 = 110,000 kg
initial velocity of second train, u2 = - 0.120 m/s
let the velocity of coupled mass after the collision is v.
Use the conservation of momentum
Momentum of trains before collision = Momentum of trains after collision

150000 x 0.3 - 110000 x 0.120 = (150000 + 110000)v
45000 - 13200 = 260000 v
31800 = 260000 v
v = 0.122 m/s
Thus, they travel with the speed of 0.122 m/s towards right after collision.