Question

3 A jet plane accelerated along a straight runway from rest to a

speed of 140m's in 50s when it took off. Calculate
its change of velocity and its acceleration​

Answer 1

Step-by-step explanation:

v=140 m/s

t=50s

u=0

change of velocity = v-u

140-0=140 m/s

for acceleration:

from Newton's first law of motion:

v=u+at

140=0+a50

50a=140

a=140/50

a=2.8 m/s²