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What is the area of 7 1/3 mm x 4 1/2 mm

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\displaystyle\bf\\7(1)/(3)~mm*4(1)/(2)~mm=\\\\\\=(7*3+1)/(3)*(4*2+1)/(2)=\\\\\\=(21+1)/(3)*(8+1)/(2)=\\\\\\=(22)/(3)*(9)/(2)=\\\\\\=(22*9)/(3*2)=\\\\\\=(11*3)/(1*1)=11*3=\boxed{\bf33~mm^2}

User Dhiraj Himani
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