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Find the equation in slope-intercept form that describes a line through (4, 2) with slope 12

2 Answers

4 votes

Answer:

The equation in slope-intercept form is Y = 12X – 46.

Explanation:

Step 1:

Using the formula .

Y – Y1 = m (X – X1)

Step 2:

Given Data:

(X1, Y1) = (4, 2)

m = 12.

Step 3:

Substitute the X1 as 4, Y1 as 2 and m as 12 in the given equation.

[Y – Y1 = m (X – X1).]

Y – 2 = 12 (X – 4)

Step 4:

Multiply 12 with (X -4).

Y – 2 = 12X – 48

Keep ‘Y’ in LHS and move -2 to RHS

Y = 12X – 48 + 2

Y = 12X – 46.

Hence Proved.

User Mot
by
5.3k points
2 votes

Answer:

The equation in slope-intercept form that describes a line through (4, 2) with slope 12 will be y = 12x -46

Explanation:

We need to find the slope-intercept form of a line that passes through (4,2) and have slope of 12.

The general form of slope-intercept form is: y= mx + b

where m is the slope and b is the y-intercept.

We are given slope m = 12

We need to find y-intercept.

Using the formula y = mx + b

and putting values y=2, x = 4 and m = 12, and finding b

y = mx + b

2 = 12(4) + b

2 = 48+b

=> b = 2-48

b = -46

So, value of b is b= -46

The equation in slope-intercept form will be:

m = 12 and b = - 46

y = mx + b

y = 12x -46

The equation in slope-intercept form that describes a line through (4, 2) with slope 12 will be y = 12x -46

User Rudolf Dvoracek
by
4.5k points