Question

Two 3.7 microCoulomb charges are 0.8 m apart. How much energy (in milliJoule) went into assembling these two charges? Enter a number with one digit behind the decimal point.

Answer 1

Step-by-step explanation:

The potential energy of a system of two charges is given by the expression

`(K* Q_1* Q_2)/(R)`

Q₁ and Q₂ are two charges and R is distance between the charges.

Given Q₁ = Q₂ = 3.7 X 10⁻⁶ , R = .8 and K = 9 x 10⁹

Putting these values in the equation we have,

`[tex](9* 10^9* 3.7*10^(-6) 3.7* 10^(-6))/(.8)`[/tex]

Potential energy = 154.01 x 10⁻³ J

This energy have been spent to bring these repelling two charges at this close distance . The energy spent have been stored as potential energy here which has been calculated.