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Find a vector parametrization r(t) for the line with the given description. Passes through P = (5, 0, 3), direction vector v = 3, 0, 5

User Kitofr
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1 Answer

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Answer:

Explanation:

Given that a line passes through a point

P = (5, 0, 3)

Direction vector =
v = 3, 0, 5

Let (x,y,z) =r(t) be any general point on the line

We have


x-5, y-0, z-3 will be proportional to v

Or
(x-5)/(3) =(y)/(0) =(z-3)/(5)

Let this equals t

Then parametric form

=
r(t) = (5+3t)i +0.j+(3+5t)k

User Matt Kuhns
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