Question

What is the electric field at a location <-0.5, -0.1, 0> m, due to a particle with charge +4 nC located at the origin?

Answer 1

138.4625 N/C

Step-by-step explanation:

We have that the charge +4 nC is at the origin (0,0,0)

We have to find the electric field at point (-0.5,-0.1,0)

We know that distance between two points is given by
`d=√((x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2)=√((0-(-0.5))^2+(0-(-0.1))^2+(0-0)^2)=0.5099m`

The electric field due to a point charge is given by
`E=(KQ)/(R^2)=(4* 10^(-9)* 9* 10^(9))/(0.5099^2)=138.4625N/C`