Question

Find two consecutive integers such that the sum of three times the first and twice the second is 27

Answer 1

For this case we have to:

Integer 1: Represented with the variable
`x`

Integer 2: It is consecutive, then it is represented with
`x + 1`

We propose the equation:

`3x + 2 (x + 1) = 27`

We apply distributive property to the terms within parentheses:

`3x + 2x + 2 = 27`

We add similar terms:

`5x + 2 = 27`

We subtract 2 from both sides:

`5x = 27-2\\5x = 25`

We divide between 5 on both sides:

`x = \frac {25} {5}\\x = 5`

Finally we have to:

`x = 5\\x + 1 = 5 + 1 = 6`

ANswer:

Consecutive integers are 5 and 6