Question

You dissolve a 1.28-g sample of nacl in a total volume of 125.0 ml of solution. your lab partner has 1.50 m aqueous nacl and wants to make a solution with the same concentration and volume as yours. how much of the solution does your lab partner need to use?

Answer 1

The 14.59 mL of solution is needed by our lab partner.

Step-by-step explanation:

Mass of the NaCl = 1.28 g

Moles of NaCL =
`n=(1.28 g)/(58.5 g/mol)=0.02190 mol`

`Molarity=(n)/(V(L))`

V = Volume of the solution in Liters.

`V_1`= 125.0 mL = 0.1250 L

Molarity of our solution =
`M_1`

`M_1=(0.02190 mol)/(0.1250 L)=0.1750 M`

Molarity of the lab partner's solution =
`M_2=1.50 M`

Volume of the lab partner's solution =
`V_2` = ?

`M_1V_1=M_2V_2`

`V_2=(0.1750 M* 0.1250 L)/(1.50 M)`

`V_2=0.01459 L=14.59 mL`

The 14.59 mL of solution is needed by our lab partner.