Question

In 1967, New Zealander Burt Munro set the world record for an Indian motorcycle, on the Bonneville Salt Flats in Utah, with a maximum speed of 183.58 mi/h. The one-way course was 5.00 mi long. Acceleration rates are often described by the time it takes to reach 60.0 mi/h from rest. If this time was 4.00 s, and Burt accelerated at this rate until he reached his maximum speed, how long did it take Burt to complete the course ?

Answer 1

Answer:49 sec

Explanation:

Given

Maximum speed to reach is 183.58 mi/h

Length of course is 5 mi

acceleration rate is defined by 60mi/h in 4 sec

therefore acceleration(a)
`=(v-u)/(t)`

`a=(60* 60* 60)/(4)`

`a=54* 10^3 mi/h^2`

To reach a speed of 183.58mi/h with an acceleration of
`54* 10^3 mi/h^2`

Using equation of motion

v=u+at

`183.58=0+(54* 10^3)t`

`t=(183.58)/(54* 10^3)`

t=0.00339 hours

t=12.23 s reach maximum speed

To complete course it takes

`s=ut+(1)/(2)at^2`

`5=0+(1)/(2)* 54* 10^3 * t^2`

t=0.01360 hour

or
`t=48.98\approx 49 s`