Question

the sole of a tennis shoe has a surface area of 0.0290 m^2. if it is worn by a 65.0 kg person, what pressure does the shoe exert on the ground?

Answer 1

Answer: 21965.517 Pa

Step-by-step explanation:

Pressure
`P` is the force
`F` exerted by a gas, a liquid or a solid on a surface (or area)
`A`, its unit is Pascal
`Pa` which is equal to
`N/m^(2)` and its formula is:

`P=(F)/(A)` (1)

In this case we have the surface of a sole of a tennis shoe:

`A=0.0290 m^(2)` (2)

And the mass
`m` of the person who wears it:

`m=65 kg`

On the other hand, we know the weight is the force
`F` the Earth exerts on people and objects due gravity
`g` :

`F=m.g=(65 kg)(9.8m/^(2))`

`F=637N` (3)

Substituting (2) and (3) in (1):

`P=(637N)/(0.0290 m^(2))` (4)

Finally:

`P=21965.517 Pa` This is the pressure the shoe exert on the ground