Answer:
![(5r+2)(3r-4)= 15r^(2)-14r-8](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5pkpmpwcqns3tle5mssm6oxufsewu24ylk.png)
Explanation:
The given expression is
![(5r+2)(3r-4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2mvlmm3up92va2973odxn1fn0zy9ife6ra.png)
To find the product of this expression, we have to use the distributive property, which is developed as follows
![5r(3r)-5r(4)+2(3r)-2(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wu9uc6jjs7w402oh0l96cz5q15cr4kzo85.png)
As you can observe, this property consists in "distributing" the first factor to the second factor. Now, we solve each product and then like terms.
![15r^(2)-20r+6r-8\\ 15r^(2)-14r-8](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cddqurz0ozyepmf0d5gly0s1wwbayf2d05.png)
Therefore, the product is
![(5r+2)(3r-4)= 15r^(2)-14r-8](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5pkpmpwcqns3tle5mssm6oxufsewu24ylk.png)