1 Answer

Jignesh Vadadoriya · Answer 1 · 2020-04-24T18:22:04+0000

For this case we must find the solution set of the following inequalities:

x-1> 11 or
$3x \leq21$

We have to:

x-1> 11

Adding 1 to both sides:

$x> 11 + 1\\x> 12$

The solution is given by all values of x greater than 12.

$3x \leq21$

We divide between 3 on both sides of:

$x \leq \frac {21} {3}\\x \leq7$

The solution is given by all values of x less than or equal to 7.

Thus, the solution set is given by:

x> 12 or
$x \leq7$

Answer:

or
$x \leq7$

(-∞, 7] U (12, ∞)

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