Question

A ray of light in air is incident on a flat piece of glass at an angle of 0 = 54° with respect to the surface. The glass has index of refraction n = 1.8. What is the angle of the refracted ray?

Answer 1

26.71°

Step-by-step explanation:

Using Snell's law as:

`n_i* {sin\theta_i}={n_r}*{sin\theta_r}`

Where,

`{\theta_i}` is the angle of incidence ( 54.0° )

`{\theta_r}` is the angle of refraction ( ? )

`{n_r}` is the refractive index of the refraction medium (glass, n=1.8)

`{n_i}` is the refractive index of the incidence medium (air, n=1)

Hence,

`1* {sin54.0^0}={1.8}*{sin\theta_r}`

Angle of refraction =
`sin^(-1)\ 0.4495` = 26.71°