Answer: 0.02055867
Explanation:
Given :
, since the alternative hypothesis is two-tailed , so the test is a two tailed test.
Sample size : n= 30
Degree of freedom for t-distribution =
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Test statistic= t= -2.43
By using the normal t-distribution table ( or calculator ) , we have
The corresponding P-value for two tailed test = 0.02055867