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When the sun has risen 32 degrees above the horizon, Sandy casts a shadow that is 9 feet 2 inches long. How tall is Sandy, to the nearest inch?

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Answer:

The height of Sandy is 68.74 inches.

Explanation:

It is given that the sun has risen 32 degrees above the horizon. It means the angle of elevation is 32°.

Let the height of Sandy be x.

Sandy casts a shadow that is 9 feet 2 inches long.

We know that 1 feet = 12 inches

Using this conversion, we get

Shadow = 9 feet 2 inches = 9(12)+2 = 110 inches

In a right angled triangle,


\tan\theta =(perpendicular)/(base)

In triangle ABC,


\tan(\angle C)=(AB)/(BC)


\tan(32^(\circ))=(x)/(110)

Multiply both sides by 110.


110\tan(32^(\circ))=x


68.73562871=x


x\approx 68.74

Therefore the height of Sandy is 68.74 inches.

When the sun has risen 32 degrees above the horizon, Sandy casts a shadow that is-example-1
User Byron Singh
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