Question

Calculate the volume in liters of a ×1.0310−6mM silver(II) oxide solution that contains 900.mg of silver(II) oxide AgO.

Answer 1

Answer : The volume of solution will be,
`7.047* 10^6L`

Explanation : Given,

Mass of AgO = 900 mg = 900000 g

conversion used : (1 mg = 1000 g)

Molar mass of AgO = 124 g/mole

Molarity of AgO =
`1.03* 10^(-6)mM=0.00103M`

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Formula used :

`\text{Molarity}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}* \text{volume of solution in liter}}`

Now put all the given values in this formula, we get the active mass of urea.

`0.00103M=\frac{900000g}{124g/mole* \text{volume of solution in liter}}`

`\text{volume of solution in liter}=7046664.579L=7.047* 10^6L`

Therefore, the volume of solution will be,
`7.047* 10^6L`