Question

How many molecules of C2H4Cl2 can be prepared from 15 C2H4 molecules and 8Cl2 molecules?

Answer 1

8 molecules of C₂H₄Cl₂

Step-by-step explanation:

Molecules of C₂H₄ = 15 molecule

Molecules of Cl₂ = 8 molecules

Molecules of C₂H₄Cl₂ =?

First of all we will write the balance chemical equation,

C₂H₄ + Cl₂ → C₂H₄Cl₂

we are given 8 molecules of Cl₂ and 15 molecules of C₂H₄, which means that 8 molecules of chlorine react with 8 molecules of C₂H₄ and will limit the reaction product. The seven molecules of C₂H₄ will remain unreactive. So , the chlorine will be the limiting reactant.

8 molecules of Cl₂ × 1 mole of C₂H₄Cl₂/ 1 mole of Cl₂

8 molecules of C₂H₄Cl₂