Question

A player rolls two dice. They lose with a sum if 2,3, or 12. What is the probability of losing on the first roll?

Answer 1

Answer:
`\bold{(1)/(9)}`

Explanation:

There is 1 possibility of getting a sum of 2 → (1 + 1)

There are 2 possibilities of rolling a 3 → (1 + 2 and 2 + 1)

There is 1 possibility of rolling a 12 → ( 6 + 6)

There are 36 total number of possible outcomes.

Consider that success for this problem is rolling a 2, 3, or 12:

`\frac{\text{number of successes}}{\text{total number of possible outcomes}}=(1+2+1)/(36)\quad =(4)/(36)\quad \implies \large\boxed{(1)/(9)}`