Answer:
Explanation:
From the given graph the coordinates of A are (8,1) and coordinates of C are (-7,7).
The point B lies on the given line AC and divides the line such that
![AB = (1)/(3)AC](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hxzfiszwvuq361japs42ckf9rdi47lqpch.png)
Thus, it can be said that the point B divides the line in the ratio 1:2.
By, section formula we have:
![B = \bigg(\displaystyle(mx_2 + nx_1)/(m+n), \displaystyle(my_2 + ny_1)/(m+n)\bigg)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/873j6q5bysluihi0sveqqmd6ldo5xhz8kc.png)
where, m:n is the ration in which the line is divided.
Here,
![m:n = 1:2\\(x_1, y_1) = (8,1)\\(x_2, y_2) = (-7,7)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kf1hac7jbliikahmd3qi83kx5y6u69fuh8.png)
Putting, all the values, we have,
![B = \bigg(\displaystyle(-7 + 16)/(3), \displaystyle(7 + 2)/(3)\bigg)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/a58b8ljnon3fnsliebaowd0kma3xo9inr3.png)
![B = (3, 3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ej5oltldudqak0g4yjbnb03htaa1rmhfwy.png)