Answer: Option E, in 12 years.
Step-by-step explanation:
A geometric growth model is characterized by its finite growth rate, known as lambda. The size of the population after a unit of time has passed can be calculated using the last known size and lamba as:
![N_(t+1) = \lambda * N_t](https://img.qammunity.org/2020/formulas/biology/college/b4k50w0yuk0depgggrykjrb1ahqf346m2w.png)
Starting from the initial value of population, the next one will be calculated multiplying by 1.4, and the next one multiplying again by 1.4, thus we can define a function that relates the time passed in year to the size of the population:
![N(t) = \lambda^(t) *N_0](https://img.qammunity.org/2020/formulas/biology/college/ge9wlmujk5c7fjfxa2ahwn68kjw0iff0g7.png)
Substituting our values we get the function that defines the growth of our poupulation:
![N(t) = 1.4^(t) *10](https://img.qammunity.org/2020/formulas/biology/college/f7lxt94k61cmi2a4zt7jkhjd467qjmuqs5.png)
Then, we just have to clear the t that gives a population of 500:
![500 = 1.4^t*10, divide\ both\ sides\ by\ 10\\50 = 1.4^t, apply\ log_(1.4)(x)\ to\ both\ sides\\log_(1.4)(50)=t\\11.63=t](https://img.qammunity.org/2020/formulas/biology/college/jyxesb051vtie1cgj9fujbotvszwsvhfc5.png)
Thus, at 12 years, the population will be greater than 500.