Question

A0.12-m-radius grinding wheel takes 5.5 s to speed up from 2.0 rad's to 11.0 rad/s. What is the wheel's average angular acceleration? a. 9.6 rad's b. 4.8 radis c. 1.6 rad/s d. 0.33 rad/s

Answer 1

The correct answer is option 'c':
`1.6rad/s^(2)`

Step-by-step explanation:

By definition of angular acceleration we have

`\alpha =(\omega _(f)-\omega _(i))/(t_(f)-t_(i))`

where,

`\omega _(f)` is the final angular velocity

`\omega _(i)` is the initial angular velocity

`{t_(f)-t_(i)` is the time in which the angular velocity is changed

Applying values we get

`\alpha =(11-2)/(5.5)\\\\\therefore \alpha =1.63rad/s^(2)`