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Paul Biggar · Answer 1 · 2020-02-25T06:10:29+0000

Answer:

(C) 21.6 pm

Step-by-step explanation:

$\lambda_i$ = Initial wavelength = 18 pm

$\lambda_f$ = Final wavelength

mc² = Eloectron rest mass = 0.511 MeV

h = Planck's constant

c = Speed of light

hc = 1240 eV nm

$\Delta \lambda=\lambda_f-\lambda_i=(hc)/(mc^2)(1-cos\theta)\\\Rightarrow \lambda_f-18=(1240)/(0.511)(1-cos120)\\\Rightarrow \lambda_f-18=3.63\\\Rightarrow \lambda_f=3.63+18\\\Rightarrow \lambda_f=21.63$

∴ Wavelength of the scattered photon is 21.63 pm

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