Answer:
The amount of product formed id determined by the limiting reagent.
Step-by-step explanation:
In a chemical reaction multiple reagents might participate. The equation of the reactions tells us how much of each reagent is needed and much product will be produced.
For example CH4 + 2 O2 => CO2 + 2 H2O
Here one molecule of methane reacts with two molecules of oxygen to for one molecule of carbon dioxide and two molecules of water.
By checking the atomic weights in the periodic table we know that 16 mols of CH4 would react with 64 mols of oxygen to form 44 mols of CO2 and 36 mols of water.
However these are perfect stechiometric ratios. In reality one or more reagents might be in excess. That excess will be left unreacted.
For example 20 mols of CH4 reacting with 64 mols of O2 would produce 44 mols of CO2, 36 mols of water and leave a leftover of 4 mols of CH4. In this case the oxygen was the limiting reagent. Note in this case that the limiting reagent was actually present in a larger amount than the excess reagent.
Depending on the molecular weights and the peculiarities of the chemical equation of the reaction either the limiting or the excess reagent might be in a larger amount.