Answer:
5.87 m/s
Step-by-step explanation:
mass of bowling ball, m1 = 7.5 kg
initial velocity of bawling ball, u1 = 8.39 m/s right
mass of bowling pin, m2 = 1.36 kg
initial velocity of bowling pin, u2 = 0
Final velocity of bowling pin, v2 = 13.9 m/s right
Let v1 be the final velocity of bowling ball.
As there is no external force is acting on the system, So the linear momentum of the system is conserved.
Total momentum before hitting = Total momentum after hitting
m1 x u1 + m2 x u2 = m1 x v1 + m2 x v2
7.5 x 8.39 + 1.36 x 0 = 7.5 x v1 + 1.36 x 13.9
62.925 = 7.5 x v1 + 18.904
44.021 = 7.5 x v1
v1 = 5.87 m /s
Thus, the final velocity of bowling ball is 5.87 m/s.