Answer:
option a is correct
net force = 28.7 N and 70º
Step-by-step explanation:
given data
first force= 17.0 N
angle = 58.0º
2nd force = -19.0 N and 12.5 N
to find out
magnitude and direction net force
solution
we know here 1st force is at angle 58.0º is 17 N
so here x component of force is F1 cosθ and y component of force is F1 sinθ
so 1st force
x component of force = F1 cosθ = 17 cos(58) = 9.0086 N ...............1
y component of force = F1 sinθ = 17 sin(58) = 14.4168 N ..............2
and 2nd force
x component of force = -19 N .................3
y component of force = 12.5 N ..................4
so net force is
net force = √(Fx²+Fy²)
net force = √((9-19)²+(14.41+12.5)²)
net force = 28.7 N
and
magnitude
tanθ = Fy / Fx
tanθ = 26.92 / 10
θ = 70º
so option a is correct