Question

A uniform film of a material that has index of refraction 1.30 covers the front surface of a pane made of glass with index of refraction 1.55. When a beam of monochromatic light initially traveling in air strikes the film at normal incidence, the minimum film thickness for which the light reflected from the air-film interface and the light reflected from the film-glass interface cancel is 115 nm .

Part A
What is the energy of each photon in the light beam?

Answer 1

The energy of each photon in the light beam is
`1.73*10^(-18)\ J`.

Step-by-step explanation:

Given that,

Index of refraction of glass =1.55

Index of refraction of material =1.30

Wavelength = 115 nm

We need to calculate the energy of each photon in the light beam

Using formula of energy

`E=(hc)/(\lambda)`

Where, h = Planck constant

`\lambda`=wavelength

c = speed of light

Put the value into formula

`E=(6.63*10^(-34)*3*10^(8))/(115*10^(-9))`

`E=1.73*10^(-18)\ J`

Hence, The energy of each photon in the light beam is
`1.73*10^(-18)\ J`.