Step-by-step explanation:
It is given that,
Frequency of the wave,
![f=5.45* 10^(14)\ Hz](https://img.qammunity.org/2020/formulas/physics/college/mbmq1chl3ntaduj6qq86sydf4qhus0gi6s.png)
We need to find the wavelength of an EM wave. The wavelength of the light is given by :
c is the speed of light
![\lambda=5.5045* 10^(-7)\ m](https://img.qammunity.org/2020/formulas/physics/college/k8aizkptzbe69u1out7h0mdya1izwrc73q.png)
or
![\lambda=550.46\ nm](https://img.qammunity.org/2020/formulas/physics/college/yh49w46yrmofan0e053olpderdur8apoer.png)
So, the wavelength of light is
. This is the wavelength of green light. Hence, this is the required solution.