Question

A student sets up two reactions. Reaction 1 uses 0.240 mol/L of reactant, and Reaction 2 uses 0.560 mol/L of reactant. How many times faster is Reaction 2 compared to Reaction 1?

Answer 1

Reaction 2 is 2.333 times faster than reaction 1.

Step-by-step explanation:

The reaction rate is measured considering the concentration of reactant used or product made and the time interval. This can be expressed in the following equation:

`rate = ([reactant])/(Δtime)`

Therefore, the higher the concentration of reactant used, the faster the reaction will be. If we consider that both Reaction 1 and Reaction 2 happen during the same time interval (Δt), we can express their rates:

`R1 = ([0.240 mol/L])/(Δt)  \\R2 = ([0.560 mol/L)/(Δt)`

Dividing R2 per R1:

`(R2)/(R1) = ((0.560 mol/L)/(Δt) )/((0.240 mol/L)/(Δt) ) = 2.333`

Thus, Reaction 2 is 2.333 times faster than Reaction 1.